5x^2=99-6x^2

Solution for 5x^2=99-6x^2 equation:

5x^2=99-6x^2

We move all terms to the left:

5x^2-(99-6x^2)=0

We get rid of parentheses

5x^2+6x^2-99=0

We add all the numbers together, and all the variables

11x^2-99=0

a = 11; b = 0; c = -99;
Δ = b2-4ac
Δ = 02-4·11·(-99)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4356}=66$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-66}{2*11}=\frac{-66}{22}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+66}{2*11}=\frac{66}{22}
=3
$